WebJul 1, 2024 · Fuglede–Putnam theorems, Berberian–Putnam–Fuglede theorems. Let $H$ denote a Hilbert space, $B ( H )$ the algebra of operators on $H$ (i.e., bounded linear … WebApr 17, 2009 · At first we investigate the similarity between the Kleinecke-Shirokov theorem for subnormal operators and the Fuglede-Putnam theorem and also we show an asymptotic version of this similarity. These results generalize results of Ackermans, van Eijndhoven and Martens. Also we show two theorems on degree of approximation on …
NOTE ON A THEOREM OF FUGLEDE AND PUTNAM
WebApr 6, 2024 · $\begingroup$ your second question is incorrect, just try a few example. Your first question... I assume that you know what the 2 norm of a vector is -- the Frobenius norm is the natural generalization of said 2 norm to matrices if you view matrices as living in a vector space.In any case the Frobenius norm is induced by an inner product and easy to … WebJan 17, 2024 · Fuglede-Putnam theorem is not true in general for $ EP $ operators on Hilbert spaces. We prove that under some conditions the theorem holds good. If the adjoint operation is replaced by Moore-Penrose inverse in the theorem, we get Fuglede-Putnam type theorem for $ EP $ operators -- however proofs are totally different. Finally, … looking glass location
Fuglede–Putnam type theorems for - SpringerOpen
WebJan 1, 1976 · Abstract. The rectangular matrix version of the Fuglede-Putnam theorem is used to prove that, for rectangular complex matrices A and B, both AB and BA are normal if and only if A ∗ AB=BAA ∗ and B ∗ BA=ABB ∗. We deduce some results relating the rank of A and the factors in a polar decomposition of A to the normality of AB and BA. WebFuglede's theorem is known to hold in this case; this follows easily from Corollary 7 of [6], p. 1935 . A similar result holds for the slightly larger class of operators called quasispectral (Theorem 1.2 in [1]) and also for the class of scalar-type prespectral operators (Theorem 5.12 in [5]). I. Colojoarä and C. Foias ([2]) introduced the WebWe will prove the following theorem. d. If Ω is a spectral set, then Ω must be a convex polytope, and it tiles the space face-to-face by translations along a lattice. ... Fuglede’s conjecture for convex bodies can thus be equivalently stated by saying that for a convex body Ω⊂Rdto be spectral, it is necessary and sufficient that the four hops in the park clement park